i am really slow when it comes to math so some help would be nice.lol.
i need help factoring this.
159 = 16t² + 5t
thanks!!
2007-12-04 15:26:54 · 11 answers · asked by lindsey 2 in Science & Mathematics ➔ Mathematics
159 = 16t^2 + 5t
159 = 21t^3
is that all you needed?
sorry if it didn't help but hope it does
2007-12-04 15:30:31 · answer #1 · answered by Anonymous · 0⤊ 3⤋
16t^2 + 5t - 159 = 0
16 can be written as 16 x 1 and 159 as 53 x 3
16 x 3 will be 48 and 53 - 48 = 5
So, we can factor the equation as
(t - 3) (16t + 53) = 0
So, t = + 3 and - 53/16
I hope you understood the working. If you need more help, email me.
2007-12-04 15:37:07 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
159 = 16t^2 + 5t
159 - 159 = 16t^2 +5t - 159
0 = 16t^2 + 5t - 159
16t^2 + 5t - 159 = 0
(t - 3) (16t + 53) = 0
2007-12-04 15:40:22 · answer #3 · answered by detektibgapo 5 · 0⤊ 0⤋
159 = 16t² + 5t
16t² +5t - 159 = 0
(16t +53)(t-3) = 0
(16t + 53) or (t-3) = 0
=> t = 3 or -53/16
2007-12-04 15:39:15 · answer #4 · answered by R L 2 · 0⤊ 0⤋
159 = 16t² + 5t
16t² + 5t-159=0
(16t+53)(t-3)=0
2007-12-04 15:35:43 · answer #5 · answered by DANIEL G 6 · 0⤊ 0⤋
159 = 16t² + 5t
0 = 16t² + 5t - 159
0 = t² + 5t/16 - 159/16
0 = ( t - 3 ) ( t + 53/16 )
Wow, LOTS of folks beat me on this one :)
2007-12-04 15:40:20 · answer #6 · answered by jgoulden 7 · 0⤊ 0⤋
16t^2+5t-159=0
(16t+53 ) (t-3)
2007-12-04 15:34:45 · answer #7 · answered by Theresa 1 · 0⤊ 0⤋
(16t-53)(t+3)
t is below |
V
t=3.3125 or -3
2007-12-04 15:37:54 · answer #8 · answered by Black Spades Rhythm Guitarist 2 · 0⤊ 1⤋
(t+53)*(t-48)=0
2007-12-04 15:36:30 · answer #9 · answered by pooja_kothiwal 1 · 0⤊ 1⤋
If you can't solve the problem, how are you going to know who to award the points to?
2007-12-04 15:30:49 · answer #10 · answered by Automation Wizard 6 · 1⤊ 2⤋