Balance this equation PLZ!. C^2H^6+ O^2 --> CO^2+ H^20?

Question

explain to me how to balace this equation

Answer 1

Each carbon leads to formation of 1 CO2
Each two H lead to formation of 1 H2O
O. on the left has to balance the O on the right, but is supplied as O2. So.........
C2H6 + ?O2 -> 2CO2 + 3H2O
From the oxygen balance, we need 3.5O2 to supply the 7 oxygens on the right. But chemists dont like decimals, so we double everything to get
2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O

Answer 2

Balance the chemical reaction.
C2H6 + O2 → CO2 + H2O
__________

You need to have the same number of each element on both sides. Start with the element that only appears in one place and do the more complicated ones after that.

Carbon only appears in one molecule on each side. So we will multiply two molecules with carbon by a and 2a, respectively to balance carbon.

a*C2H6 + O2 → 2a*CO2 + H2O

Now we will balance hydrogen. And we will use a and 3a, respectively.

a*C2H6 + O2 → 2a*CO2 + 3a*H2O

Now balance oxygen.

(2a*2 + 3a)/2 = 7a/2

a*C2H6 + (7a/2)*O2 → 2a*CO2 + 3a*H2O

We need integral coefficients. Multiply thru by 2.

2a*C2H6 + 7a*O2 → 4a*CO2 + 6a*H2O

Now we can eliminate the arbitrary constant a.

2(C2H6) + 7(O2) → 4(CO2) + 6(H2O)

And on each side we have:

C = 4 atoms
H = 12 atoms
O = 14 atoms

So it is balanced.

Answer 3

First initiate by potential of doubling the hydrocarbon 2C2H6 then stability the kind of carbons with 4CO2 molecules and the kind of hydrogens with 6 water molecules. ultimately stability the kind of oxygens with 7 O2 molecules. once you are going to be able to desire to stability those style of reactions that is oftentimes efficient to double the kind of hydrocarbon molecules to start. be effective to earnings my artwork to determine that that is genuine.:>)

Answer 4

I assume H2O, not H20.

to get 6H we need 3H2O
to get 2C we need 2CO2
7O on right, so 3.5 O2 on right. so double everything

2C2H6 + 7O2 --> 4CO2 + 6H2O


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