Help plzzz.....?

Question

A block of aluminum weighing 140.0 g is cooled from 98.4° C to 62.2° C with the release of 1080 cal of heat. From these data, calculate the specific heat of aluminum

Answer 1

The relationship you need is

Q = m c ΔT

where

Q is the heat added or removed ( 1080 calories )
m is the mass ( 140.0 grams )
c is the specific heat ( unknown )
ΔT is the change in temperature ( 62.2 - 98.4 oC )

Plug in the values and solve for c. The units will be calories / gram-oC