Solve the Quadratic equation...?

Question

0= x^2+2x+16

Answer 1

[20]
x^2+2x+16=0
comparing the equation with standard quadratic equation,we get
a=1 , b=2 and c=16
x={-2+-sqrt(4-64)}/2
=(-2+-sqrt(-60)/2
=(-2+-2sqrt15i)/2
=-1+-sqrt15i

Answer 2

For your reference, the Quadratic Formula states that the equation
a*x^2 + b*x + c = 0
has the following answers:
x = -b +or- sqrt(b^2 - 4*a*c) all divided by 2*a

You have the equation
1*x^2 + 2*x + 16 = 0
So a=1, b=2, and c=16. Thus, your answers contain the expression
sqrt(b^2 - 4*a*c) = sqrt((2)^2 - 4*1*16) = sqrt(-60)

Thus, your answers will not be real numbers! When you work out the quadratic formula, you will eventually get
x = -1 +or- (sqrt -15)*i

Cheers,
Nicholas

Answer 3

0= x^2+2x+16
Complete the square
-15 = x^2 + 2x + 1
-15 = (x+1)^2
sqrt(-15) = x + 1
x = -1 +/- i*sqrt(15)

Answer 4

-2+-square roots of 2^2-4x1x16/2x1
+ or - the square root of 60