2007-12-04 13:42:16 · 8 answers · asked by tiberouscain 1 in Science & Mathematics ➔ Mathematics
the x cancels out and you're left with 20 = 0, which is not a valid equation.
This is like saying, think of a number, add 20 now take away the first number you thought of. Whatever you thought of you're going to be left with 20, _not_ 0.
2007-12-04 13:46:59 · answer #1 · answered by perplexed* 3 · 0⤊ 0⤋
x+20-x =0
=> (x -x) = -20
=> 0 = -20 => no solution
Verification
It's obvious to verify this equality
x = 0 => 20 = 0
x = 1 => 20 = 0
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x = 1000 => 20 = 0
etc
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Conclusion:
For all real numbers this equation(x+20-x = 0) has no solution.
2007-12-04 21:54:52 · answer #2 · answered by frank 7 · 0⤊ 0⤋
you cannot. the x's subtract out of the problem leaving you with 20 = 0
this is not a true statement. Thus, there is no solution
2007-12-04 21:45:44 · answer #3 · answered by Linda K 5 · 0⤊ 0⤋
substract 20 from both side.
x+20-x=0
-20 -20
x+-x=0-20
0 =-20
x cancels out
I think.
2007-12-04 21:47:23 · answer #4 · answered by ckm0917 2 · 0⤊ 0⤋
No such x exists. The x and -x cancel and you are left with
20=0
which is clearly false.
Cheers!
Nicholas
2007-12-04 21:46:01 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x + 20 -x = 0
20 = 0
impossible
did you write it down right?
2007-12-04 21:46:05 · answer #6 · answered by Steve A 7 · 0⤊ 0⤋
there is no solution to this set, because the x's cancel each other out
2007-12-04 21:45:45 · answer #7 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
there is no solution to this problem because no matter what x is, the equation will never be true
2007-12-04 21:45:53 · answer #8 · answered by someone else 7 · 0⤊ 0⤋