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An airplane traveling at 201 m/s makes a turn. What is the smallest radius of the circular path (in km) that the pilot can make and keep the centripetal acceleration under 5 m/s^2?

2007-12-04 12:43:38 · 2 answers · asked by SICK MY DUCK! 1 in Science & Mathematics Physics

2 answers

Centripetal acceleration = v^2 / r = 5m/s^2

r = v^2 / a = [201] ^2 /5 = 8080.2m

From a = v^2/ r
If the acceleration should be below 5m/s^2, then r should be more than 8.0802 km.

Hence the radius must not be less than 8.0802 km.
That is to say 8.1 km.

2007-12-04 13:05:20 · answer #1 · answered by Pearlsawme 7 · 1 0

The centripetal acceleration is v^2/R.

2007-12-04 20:50:09 · answer #2 · answered by gp4rts 7 · 0 0

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