Find four solutions for the equation 3x + 5y = 15?

Question

Find four solutions for the equation 3x + 5y = 15



This one definitely has me stumped. Any help would be great. Also if you could show me how you come to your answer it would be great. Thanks in advance.

Answer 1

3x + 5y = 15
5y = 15 - 3x
y = 15/5 - 3/5x
y = 3 - 3/5x

x = 0, y = 3 - 3/5(0) = 3
x = 5, y = 3 - 3/5(5) = 0
x = 10, y = 3 - 3/5(10) = -3
x = 15, y = 3 - 3/5(15) = -6

Answer 2

x = - 5 y = 6 , x = 10 y = -3 , x = 1 y = 3 x = 0 y = 3

Answer 3

Just pick any value for x and solve for y. Or pick any value for y and solve for x.

For example x = 0:
3(0) + 5y = 15
5y = 15
y = 3

So one solution pair is (0, 3)

Or try y = 0:
3x + 5(0) = 15
3x = 15
x = 5

So another solution pair is (5, 0)

How about x = -5:
3(-5) + 5y = 15
-15 + 5y = 15
5y = 30
y = 6

So (-5, 6) is another pair.

You might get fractions, but those are valid too:

x = 1
3(1) + 5y = 15
5y = 12
y = 12/5

Another solution is (1, 12/5)

Answer 4

Simplifying
3x + 5y = 15

Solving
3x + 5y = 15

Move all terms containing y to the left, all other terms to the right.

Add '-3x' to each side of the equation.
3x + -3x + 5y = 15 + -3x

Combine like terms: 3x + -3x = 0
0 + 5y = 15 + -3x
5y = 15 + -3x

Divide each side by '5'.
y = 3 + -0.6x

Simplifying
y = 3

Answer 5

just plug and chug

put in an arbitrary number for x (say 2)
substitute 2 for x in the equation and you have:
3 * 2 + 5y = 15
or 6 + 5y = 15
that means that 5y = 9
so y = 9/5 if x = 2

now try it with x = 3

3 * 3 + 5y = 15
9+5y = 15
5y = 6
y = 6/5 if x = 3

finally, try this with x = 4
3*4 + 5y = 15
12 + 5y = 15
so 5y = 3
y = 3/5 if x = 4

Answer 6

3x + 5y = 15


This has an infinite number of solutions

pick any x and calculate y = (15 -3x)/5

example:
x =5 ----> y =0 is a solution
x =1 ----> y =12/5
x =2 ---> y = 9/5
x =3 ---> y = 6/5

Answer 7

Pick any 4 values of x, and then put them into the equation and solve for the corrosponding values of y. The solutions will be ordered pairs.

So for example, lets pick x=0

3(0) + 5y = 15
5y = 15
y = 3

So one solution is x=0, y=3, or (0,3)

You could also graph that line, and any point which the line passes through will be a solution to the equation.

Answer 8

3x + 5y = 15
3x = 15 - 5y
x = 5 - 5y/3
5 - 5y/3 + 5y = 15
5 - 5y/3 + 15y/3 = 15
10y/3 = 10
y/3 = 1
y = 3
3x + 5(3) = 15
3x + 15 = 15
3x = 15 -15
3x = 0
x = 0
therefor
if you put
x=0 and y=3 (first soluation)
or
x=5 and y=0 (second soluation)
....third and forth soluations can not be found
well there is only two variables and one equation
therefor two soluation can be found

Answer 9

x^n+y^n=z^n
n>2

Answer 10

well the two obvious answers are x=0 y=3 and x=5 y=0 not sure about the other two