Need help with physics question PLEASE!!?

Question

I need help solving this question, and I would really appreciate it if you took the time to walk me through it.

A 100 N block is positioned on an incline that makes a 25° angle. The coefficient of kinetic friction between the block and the incline is 0.15. A force of 125 N is applied by pulling a rope at a right angle of 35° above the incline.

a) (It says to draw free body diagram, but I know that's annoying to do, so can you just label the weight, its components, the friction force, the tension, and its components?)

b) Determine the magnitude and direction of the acceleration of the block.

What I'm having trouble with is that I don't know if factors like the normal force are made the addition of the perpendicular component of gravity as well as the perpendicular applied force of the rope? Or is it difference between the 2, because the rope is being pulled up, sort of relieving the actual perpendicular force of the weight?

Because there's a lifting force of the string, not a force pushing into the surface of the incline, would the normal force consist of the perpendicular component of gravity subtracted by the perpendicular force of the applied string, because it's getting lifted, taking away from the weight on the surface?

Answer 1

The weight 100 N acts vertically DOWN.
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You have stated that a force of 125 N is applied by pulling a rope at a RIGHT angle of 35° above the incline.
It has no meaning. I hope it must be a rope at an angle of 35° above the incline
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This force in effect pulls the block upward; hence the block presses the plane some what less than that if this force was absent.
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Hence the normal reaction is one which is less than the normal reaction when the pulling rope was absent.
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125 cos 35 - 100 sin 25 = 60.13 N is the force pulling the block up the plane. --------------------1.

The normal reaction of the plane acting on the block is
100 cos 25 - 125 sin 35 = 18.93.

The frictional force is therefore, 0.15 * 18.93 = 2.84 n

The net force pulling the block up is 60.13 - 2.84
= 57.29N

The acceleration of the block is [57.29 / 100 ] g = 5.61 m/s^2

Answer 2

While you don't know the normal force, you can calculate it, since you know there's gravity, friction, and that lifting force on a string. Calculate two "net" vectors... perpendicular to slope, and along the slope. You need the perpendicular one to calculate friction, which will give you the net "along slope". That and mass will give you to acceleration.