a(t)=-32 ft/sec squared. An object is thrown vertically down from the top of a 480 foot building with an initial velocity of 64 feet/second.What is the objects velocity right before it hits the ground?
2007-12-04 12:31:02 · 3 answers · asked by jo l 1 in Science & Mathematics ➔ Physics
This is kinematics. You know acceleration, distance, and initial velocity.
Use
v(final) ^2 = v(initial)^2 + 2 * a * d
2007-12-04 12:59:46 · answer #1 · answered by Clueless Dick 6 · 1⤊ 0⤋
What's so difficult about this question? Is the initial velocity throwing you off? Or the height? You can do this the brute force way, or the Integral math way. It's up to you.
2007-12-04 20:50:03 · answer #2 · answered by Kasey C 7 · 0⤊ 1⤋
From gravity, v^2= 2ad
V(final) = sqrt (2ad) + 64ft/sec where a = 32 ft/sec^2, d=480ft
2007-12-04 20:59:52 · answer #3 · answered by LucaPacioli1492 7 · 0⤊ 1⤋