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2^(x+3) + 2^x = 18 And 3^2x - 10(3^x) + 9 = 0

2007-12-04 12:05:02 · 1 answers · asked by jeffnellytherock 1 in Science & Mathematics Mathematics

1 answers

For the first problem,

2^(x+3) = (2^x)( 2^3) = 8 (2^x)

Now combine terms on the left side.

For the second problem, note that

3^(2x) = (3^x)²

Let y = 3^x. Then you have a quadratic equation for y. Solve it for y, then set 3^x equal to each y-solution and solve for x.

2007-12-04 12:58:57 · answer #1 · answered by Ron W 7 · 0 0

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