How much energy is required to melt 0.89 kg of ice? Answer in J.?

Answer 1

Heat of fusion of water: 333.55 kJ/kg
Suppose the ice was at 0°C, and water generated by melting the ice is also at 0°C. The answer is:
(333.55 kJ/kg)*(0.89 kg) = 3.0x10^2 kJ = 3.0x10^5 J
I take 2 significant figures, since the given data is also with 2 significant figures.