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f(x) = 2 / [(lnx) - 6]

Lim x→∞ of {2 / [(lnx) - 6]} = 0/∞ = 0
The horizontal asymptote is y = 0.

A vertical asymptote occurs when the denominator is zero. That will occur when:

lnx - 6 = 0
lnx = 6
x = e^6

The vertical asymptote is x = e^6.

2007-12-04 11:52:35 · answer #1 · answered by Northstar 7 · 0 0

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