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9 answers

Since it is parallel to y = 3x - 7, the slope will be 3. (Parallel lines have the same slope).

Now you need to write the equation for a line with slope of 3 and through the point (0, 4).

Start with the point-slope form of a line:
y - y1 = m(x - x1)

Your point is x1 = 0, y1 = 4.
Slope is 3:

y - 4 = 3(x - 0)

Now simplify:
y - 4 = 3x

Add 4 to both sides:
y = 3x + 4

2007-12-04 11:27:14 · answer #1 · answered by Puzzling 7 · 0 0

A line parallel to the given line y = 3x - 7 must look like -

where c is a constant which has to be calculated.

y = 3x + c As this line passes through (0,4) -

4 = 3(0) + c
=> c = 4
Substituting c = 4 in the eqn y = 3x + c , we get the required eqn.

y = 3x + 4 ............. Answer

2007-12-04 11:31:09 · answer #2 · answered by Pramod Kumar 7 · 0 0

Parallel lines have the same slope, so with that information, we know our equation so far looks like this:

y = 3x + b

Now (0,4) happens to be where the line crosses the y-axis. The y of this ordered pair is the b in the above equation (b stands for y-intercept), so the final equation should look like this:

y = 3x + 4

2007-12-04 11:28:06 · answer #3 · answered by Zandia 3 · 0 0

Take the by ability of-made from the equation of the curve and make y the area contained in the equation of the instantly line: y' = 2e^x - 3 y = 3x - 6 If 2 strains are parallel then their gradients are equivalent, an excellent thanks to set the gradients to equivalent each diverse: 2e^x - 3 = 3 2e^x = 6 e^x = 3 x = ln(3) Now change that element lower back into between the needed equations to seek out the y coordinate: y = 8 + 2e^(ln(3)) - 3ln(3) y = 14 - 3ln(3) element = (ln(3), 14 - 3ln(3))

2016-10-25 11:18:41 · answer #4 · answered by Anonymous · 0 0

y=3x+4

use equation y=mx+b.
since it has to be parallel the slope remains 3.
so we get: y=3x+b.
plug 4 in for y
plug 0 in for x
this gets you 4=3(0)+b
since 3 times 0 is zero: b=4

2007-12-04 11:35:14 · answer #5 · answered by Anonymous · 0 0

the parallel line will have the same slope

The y-intercept is the point (0,4)

y=3x+4

2007-12-04 11:27:55 · answer #6 · answered by Lady Lefty 3 · 0 0

line parallel to y = 3x -- 7 and passing through (0, 4) is
y = 3x + (4 -- 3*0) or y = 3x + 4

2007-12-04 11:32:38 · answer #7 · answered by sv 7 · 0 0

You have the slope (parallel lines have the same slope) and you have the y-intercept (0,4). Therefore, the equation you are looking for is:

y = 3x + 4

that's it! :)

2007-12-04 11:27:53 · answer #8 · answered by Marley K 7 · 0 0

Parallel lines have the same slope.

y=3x___

4=0+4

y=3x+4 <---- answer

2007-12-04 11:28:00 · answer #9 · answered by rabie_babies 1 · 0 0

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