2007-12-04 10:24:47 · 25 answers · asked by Ashley W 2 in Science & Mathematics ➔ Mathematics
X= 2.333 OR 2 and 1/3
3x(3x-7)=0
9x^2 - 21x = 0
9x^2=21x (divide everything by x)
9x=21
x=2.333
2007-12-04 10:32:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
This means that either 3x = 0 or 3x - 7 = 0
So x = 0 or x = 7/3
2007-12-04 10:28:14 · answer #2 · answered by Anonymous · 1⤊ 1⤋
x = 0 , x = 7/3
2007-12-08 03:53:57 · answer #3 · answered by Como 7 · 1⤊ 1⤋
not sure if you wrote the question right. the way i read that x=0
3*0=0 so you would have 0(0-8)=0
if the problem is 3(3x-7)=0
then the answer is 7/3
3(3x-7)=0
= 9x-21=0
9x=21
x=21/9
x=7/3
2007-12-04 10:32:20 · answer #4 · answered by DisneyKrayzie 4 · 0⤊ 0⤋
x=7/3
2007-12-04 10:27:23 · answer #5 · answered by Anonymous · 1⤊ 0⤋
are you trying to find x? try and set both = 0, so 3x=0 and 3x-7=0 because if either multiple is zero then the equation is correct, and then solve for x.
x=0, 7/3
2007-12-04 10:31:24 · answer #6 · answered by lohpanred 2 · 1⤊ 1⤋
3x(3x-7)=0, only if 3x=0 or 3x-7=0
3x=0 => x=0
3x-7=0 => 3x=7 => x=7/3
2007-12-04 10:28:18 · answer #7 · answered by LDJ 3 · 0⤊ 0⤋
OK
x can be 0 or 7/3.
Hope that helps.
2007-12-04 10:34:50 · answer #8 · answered by pyz01 7 · 0⤊ 0⤋
3x(3x-7)=0
3x = 0 or 3x-7 = 0
x = 0 or x = 7/3
2007-12-04 10:27:44 · answer #9 · answered by RickSus R 5 · 2⤊ 0⤋
multiply both sides by 3x so
3x - 7 = 0
add 7 to both sides so
3x = 7
divide both sides by 3 so
x = 7/3
I don't know why everyone is making it so hard with exponents and if statements. seems easy enough to me like this.
2007-12-04 10:35:01 · answer #10 · answered by sam 4 · 0⤊ 0⤋
eather
3x=0
then x=0
or
3x-7=0
then
3x=7
x = 7/3
therefor x has true values they are
0 , 7/3
2007-12-04 12:34:23 · answer #11 · answered by Rayan Ghazi Ahmed 4 · 0⤊ 0⤋