How many moles of O2 are present in 44.8L of O2 at STP?
How many moles of CO2 are present in 4.00L of CO2 gas at STP?
What volume in liters is occupied by 2.5 moles on N2 at STP?
2007-12-04 09:40:53 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
You use the ideal gas law.
PV = nRT
where P = pressure
V= Volume
n = number of moles
R = gas constant
and T = temperature.
STP is V = 22.4 L, P = 1 atm, and T = 273 K
Since your problem gives you volume, you plug that in for volume and then just plug in your STP numbers and solve for n. It's algebra, basically.
n = PV / RT
n = (1 atm)(44.8L) / (.0821)(273 K)
n = 1.9988
with significant figures, n = 2.00
Just do the same for your other problems. It's easy!
2007-12-04 09:48:54 · answer #1 · answered by michelle8 4 · 1⤊ 0⤋
How many moles of O2 are present in 44.8L of O2 at STP?
1 mole O2 / 22.4 l = X / 44.8 l X = 2 moles
How many moles of CO2 are present in 4.00L of CO2 gas at STP?
1 mole CO2 / 22.4 l = X / 4.00 l X = 0.179 liters
What volume in liters is occupied by 2.5 moles on N2 at STP?
22.4 l / 1mole N2 = X / 2.5 mole N2 X = 56.0 liters
2007-12-04 17:49:15 · answer #2 · answered by Dennis M 6 · 0⤊ 0⤋
Remember that 1 mole of any gas at STP occupies 22.4 liters which is known as the molar volume.
1) Divide 44.8 liters by 22.4 liters/mole to get moles
2) Divide 4.00 liters by 22.4 liters/mole
3) Multiply 2.5 moles by 22.4liters/mole to get liters
2007-12-04 17:52:33 · answer #3 · answered by lynx 3 · 0⤊ 0⤋
Earth, you are lazy. They are practically giving you the answer. AT STP, 1 MOLE OF ANY IDEAL GAS OCCUPIES 22.4 Liter. The rest is proportions. Hop to it,
2007-12-04 17:51:35 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋