word problem...need help please?

Question

The combined resistance of two resistors R1 and R2 in a parallel circuit is given by the formula...simplify formual.

R =1/ 1/R1+1/R2
T

Answer 1

Hers's the steps to reduce
1. put denominators over common denominator (R1R2) and you will get R2+R1/R1R2
2. When dividing by a fraction (or any term), you can simply multiply by the reciprocal. The reciprocal of R2+R1/R1R2 is done by simply exchanging the numerator and the denominator. In this case, you get R1R2/R2+R1. So the problem turns out to be
1/1/* R1R2/R2+R1 which equals R1R2/R2+R1
3. Your done!

Hope this helps - Good luck - M

Answer 2

This is a fancy edition of dividing one fraction by another.
R= 1 / 1/R(1) + 1 / R(2)
Deal with the mess on the bottom first.
1/R(1)+1/R(2) has R(1) X R(2) as a common denominator.
Therefore. 1/R(1)+1/R(2)= {R(2)+R(1)} / R(1)R(2)
Our problem is now, 1 / {R(2)+R(1)}/R(1)R(2)
This can be written as 1/1 / {R(2)+R(1)}/R(1)R(2)
We know how to handle this! Turn the bottom fraction upside down, and multiply it by the original
problem's numerator.
Our problem now becomes 1/1 X R(1)R(2)/R(2)+R(1)
=R(1)R(2) / R(2)+R(1)
Picky math teachers like to see it written as
R(1)R(2) / R(1)+R(2)

Answer 3

sorry barely passed kindergarten math good luck

Answer 4

wow thats hard