given: Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.4 degrees celsius. A 250 mL sealed flask contains 0.55g of butane at - 22 degrees celsius.
How much butane is present as a liquid?
I got 0.25g
so I can't do the next question...
If the butane is warmed to 25 C , how much is present as a liquid?
2007-12-04 08:30:39 · 3 answers · asked by Pooh 4 in Science & Mathematics ➔ Chemistry
the program says 0.25g is not right?!
2007-12-04 08:37:02 · update #1
If you are below the boiling point, all of the substance will be a liquid. Therefore all 0.55g of butane will be a liquid at -22°C (negating the VERY small amount lost from evaporation).
Likewise, 25°C is well above the boiling point which means all of your substance will be a gas. So, 0 g of your substance will still be a gas at that temperature.
2007-12-04 08:35:39 · answer #1 · answered by lhvinny 7 · 3⤊ 0⤋
pV=nRT
As the container is sealed just plug in values... gas constant is 8.31kj/mol
2007-12-04 08:40:05 · answer #2 · answered by Agi 2 · 1⤊ 4⤋
All of it.
2007-12-04 08:32:49 · answer #3 · answered by Anonymous · 0⤊ 2⤋