2006? That would be your hundredth season, unless my math is wrong (which it often is).
You can't just add 100 to 1907, because the 1907 season itself would be year one. The 100th season would be 2006, so it depends if you're celebrating the beginning or that season, or the start of your 101st season.
Amy - If you start in 1907, 2006 is your 100th season. Any time you add or subtract inclusive seasons, you have to account for the inital one. It would be 2006-1907 = 99, plus one for the initial season, equalling 100. If you don't believe me, just count it out.
2007-12-04 07:26:11
·
answer #1
·
answered by Craig S 7
·
3⤊
3⤋
2007 should be the 100th year anniversity of something that started in 1907, in less you do your math like Craig S does. Just as if next year it will be the 100 years annveirsty of the last time the Chicago Cubs last won the World Series. But that can always be the good question. IN less you cout the first year in 1907,, and get it to where the 100th would be 2006, even through it would be 99 years. All this math might start making my head hurt.
2007-12-04 09:32:53
·
answer #2
·
answered by staggmovie 7
·
0⤊
0⤋
2007
2007-12-04 07:48:49
·
answer #3
·
answered by sportsmanbjf 2
·
1⤊
1⤋
2007
2007-12-04 07:27:05
·
answer #4
·
answered by Senderson 1
·
1⤊
2⤋
IN 2006
2007-12-04 15:42:01
·
answer #5
·
answered by The Ghost of Shasta 6
·
0⤊
0⤋
2008
2007-12-04 07:27:41
·
answer #6
·
answered by Anonymous
·
0⤊
3⤋
1907 + 100 = 2007 Thats the answer 2007 hope that's what you needed.
2007-12-04 07:29:23
·
answer #7
·
answered by Minustone 2
·
1⤊
2⤋
Chris is right. 1907 is Year 1, making 2006 Year 100. It's that whole inclusive-exclusive mathematics y'all slept through in High School, while us nerds were taking over the world! LOL
2007-12-04 08:08:56
·
answer #8
·
answered by pricehillsaint 5
·
0⤊
1⤋
2008, because 1907 - 2007 is only 99 years.
Just like 1/1/01 was the 1st year of the 21st century.
2007-12-04 07:43:07
·
answer #9
·
answered by Qbass187 4
·
0⤊
4⤋
2007?
2007-12-04 07:26:30
·
answer #10
·
answered by Anonymous
·
0⤊
3⤋