what is the sum of the divisors of 42?

Answer 1

If we consider divisors that lie in the ring of integers, then we must simply add 1,2,3,6,7,14,21, and 42 for a sum of 96.

Answer 2

What are the divisors of 42?
Guess 2 as one of them - it's even,
2 * 21 = 42.
Now divide 21 into 7 and 3

2 * 3 * 7 = 42, and all divisors are prime, so we have found the prime divisors. (depending the number, you might have more than one instance of a particular prime divisor.)

I suspect the question might be asking for the sum of prime divisors in which case, the answer is 12 (or 13 if you include 1)

If the question is asking for all divisors:
Multiply out all combinations of the prime divisors to get all divisors.

2 * 3 = 6
2 * 7 = 14
3 * 7 = 21

So all divisors are
2,3,6,7,14,21 (some people include 1 and 42 as well)
sum = 53
or 96 if you include 1 and 42.

Answer 3

The integer divisors of 42 would be:
1, 2, 3, 6, 7, 14, 21, 42.

And technically you have the negative divisors too:
-1, -2, -3, -6, -7, -14, -21, -42

However, then the sum would be 0, so I think they must have intended for you to give the sum of the *positive integer divisors*.

1 + 2 + 3 + 6 + 7 + 14 + 21 + 42 = 96

Answer 4

Divisors Of 42

Answer 5

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RE:
what is the sum of the divisors of 42?

Answer 6

42 as any other number has dozen of thousands of divisors, but if we strictly enclose to the prime factors of 42 (2x3x7), their sum is 12.