17(5)
2007-12-04 07:03:25
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answer #1
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answered by Anonymous
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85 times 1. or 1 times 85.
17 times 5, 5 times 17
2007-12-04 07:04:48
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answer #2
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answered by Anonymous
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85/7 x 7/3 x 3/25 x 25/6 x 6/1 = 85
I got some others also.
Numbers that end in 2 are divisible by 2. Ending in 5 they are divisible by 5. Check out other rules.
2007-12-04 07:08:38
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answer #3
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answered by baja_tom 4
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For future reference: any number that ends in a 0 or a 5 is divisible by 5. So you can divide the number by 5 to obtain the other factor.
2007-12-04 07:08:09
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answer #4
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answered by Michael M 7
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5 and 17.
2007-12-04 07:06:43
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answer #5
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answered by sure.ill.dance. 1
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For the integer factors, only 1 * 85.
For the real factors a lt. (e.g. 42.5 * 2 = 85)
2007-12-04 07:45:22
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answer #6
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answered by CatNip 6
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The prime factorization of 85 is 5X17.
2007-12-04 07:04:07
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answer #7
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answered by Anonymous
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Here's a clue: any number that ends in either 5 or 0 must be divisible by what digit?
2007-12-04 07:11:25
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answer #8
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answered by Old math guy 1
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yeah your brain cells multiplied by the fingers u have on one hand
so 17 x 5
2007-12-04 07:08:56
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answer #9
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answered by Anonymous
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17*5. ANS.
2007-12-04 07:04:32
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answer #10
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answered by Anonymous
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