of 60 degrees at a distance of 44 feet from the base?
2007-12-04 07:00:17 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
76.2 ft
2007-12-04 07:02:29 · answer #1 · answered by chcandles 4 · 0⤊ 0⤋
draw a diagram of this and it makes it easier.
you are looking for the other leg of a right triangle.
use the tangent trig function to find the height
tan 60 = height / 44
height = 44tan60
exact height = 44 times sqrt of 3
approximate height would be = 76.2 feet
2007-12-04 07:07:03 · answer #2 · answered by Ray 5 · 0⤊ 0⤋
height/distance = tan 60
h = 44 x tan 60 = 76.2
2007-12-04 07:04:30 · answer #3 · answered by norman 7 · 0⤊ 0⤋
By def Tan(theta) = y/x
Tan(60) = y/44
1.7320 = y/44
1.7320 * 44 = y
76.208 is the height of the building
2007-12-04 07:52:14 · answer #4 · answered by CatNip 6 · 0⤊ 0⤋
76'-2 1/2". Units, .2102 feet is a little less than 17/32".
2007-12-04 07:08:56 · answer #5 · answered by Johneye 4 · 0⤊ 0⤋