if it is a cubic polynomial 3
number of roots = highest power of equation
2007-12-04 06:54:08
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answer #1
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answered by Stephen Y 6
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A polynomial of degree 3 has three roots in the complex field. This is simply an instance of the Fundamental Theorem of Algebra. If the cubic has real coefficients, then the number of real roots must be either 1 or 3, because under this hypothesis complex roots must occur in conjugate pairs (because complex conjugation is an R-linear automorphism of the complex field). I hope this has been helpful. Adieu!
2007-12-04 07:00:52
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answer #2
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answered by Anonymous
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A polynomial of third degree has both one or 3 genuine roots, so the answer is c. As another answerer suggested, an imaginary root must have a conjugate, so there can not be 2 genuine roots and one imaginary one.
2016-10-25 10:54:58
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answer #3
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answered by Anonymous
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The answer depends on the context for the question.
If you are talking about roots that are real numbers, then a polynomial of degree n can have at most n roots.
If you allow for complex roots, and if you count roots corresponding to repeated factors as "repeated roots", then every polynomial of degree n has exactly n roots.
So if n=3, there's your answer.
2007-12-04 06:52:26
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answer #4
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answered by Michael M 7
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The maximum number of roots of a polynomial is equal to the degree of the polynomial. For example, a fifth-degree polynomial has five roots.
2007-12-04 06:48:37
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answer #5
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answered by jgoulden 7
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count the number of the change of sign in each term of the polynomial
if the polynomial all have + sign . .. there is no root
Ziah X equation has 1 root because there is a change from + to - in the last two terms
2007-12-04 06:49:04
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answer #6
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answered by CPUcate 6
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The max number of roots is equal to the degree of the highest variable. If you want to know how many are real or imaginary, I would try using Descartes' Rule of Signs.
2007-12-04 06:51:06
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answer #7
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answered by Anonymous
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The Maximum equals the minimum.
2007-12-04 06:46:42
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answer #8
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answered by The Source 3
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