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Solve:

N= 3(pi) √(1/P) for P

(pi)=3.14

2007-12-04 05:47:17 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

N= 3(pi) √(1/P) (P>0)
[N/(3pi)] = √(1/P)
1/P=[N/(3pi)]^2
P=1/{[N/(3pi)]^2}

2007-12-04 05:55:46 · answer #1 · answered by tinhnghichtlmt 3 · 0 0

Square terms to take 1/P out of the square root:
N^2 = 9 pi^2 * 1/P.
Divide so as to isolate 1/P:
1/P = N^2/9 pi^2,
P = 1/(N^2/9 pi^2),
P = 9 pi^2/N^2,
P = 88.7/N^2 [ans].

2007-12-04 14:17:51 · answer #2 · answered by BB 7 · 0 0

Wtite
N^2 = 9(pi)^2 / P

then

P = etc

2007-12-04 13:55:27 · answer #3 · answered by lienad14 6 · 0 0

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