Please help with Algebra question
2007-12-04 01:47:45 · 10 answers · asked by shellyeph 1 in Science & Mathematics ➔ Mathematics
(2x-1)(7x+3) = 14x^2 -x -3 ft^2
2007-12-04 01:55:14 · answer #1 · answered by ironduke8159 7 · 3⤊ 0⤋
Area = Length x Width
Area = (7x + 3) x (2x - 1)
Area = 14x^2 -7x +6x - 3 ~ FOIL (Multiply First terms, Outer Terms, Inner terms, Last Terms)
Area = 14x^2 -x - 3 ~collect like terms where {x^2 is x squared}
Final Answer: Area = 14x^2 -x - 3
2007-12-04 01:57:32 · answer #2 · answered by mrcosine 1 · 0⤊ 1⤋
Area of a rectangle = lxw
= (2x-1) (7x+3)
= 14x^2-7x-3+6x
= 14x^2-x-3
2007-12-04 01:53:24 · answer #3 · answered by surmy 2 · 1⤊ 1⤋
A = ( 2x - 1 ) ( 7x + 3 )
A = 14 x ² + 6x - 7x - 3
A = 14 x ² - x - 3 ft ²
2007-12-04 01:53:42 · answer #4 · answered by Como 7 · 3⤊ 1⤋
Since area of a rectangle is l x w (length times width) the area of your "algebraic" rectangle is
A = (7x-3)(2x-1) which you should be able to multiply out. If you can't check your text index for multiplying polynomials.
2007-12-04 01:52:27 · answer #5 · answered by baja_tom 4 · 1⤊ 1⤋
multiplt hte binomials:
2x times 7x = 14x^2
2x times 3= 6x
-1 times 7x = -7x
-1 times 3 = -3
now add the terms
14x^2 -x-3
2007-12-04 01:59:13 · answer #6 · answered by mom 7 · 0⤊ 2⤋
(2x-1)*(7x+3) = 14x^2+6x-7x-3
= 14x^2 -x -3 square feet
2007-12-04 01:56:15 · answer #7 · answered by Anonymous · 0⤊ 2⤋
(2x-1)(7x+3)
= 14x^2 +6x-7x-3 ft^2
= 14x^2 -x -3 ft^2
2007-12-04 01:58:18 · answer #8 · answered by Essien 3 · 0⤊ 1⤋
14x^2-x-3 ft^2
2007-12-04 01:57:28 · answer #9 · answered by Joker 2 · 0⤊ 1⤋
complicated point. research on to yahoo and bing. just that can assist!
2016-04-07 07:44:35 · answer #10 · answered by Anonymous · 0⤊ 0⤋