The windpipe of a typical whooping crane is about 5.3 feet long. What is the lowest resonant frequency of this pipe, assuming that it is closed at one end? (Assume a temperature of 35°C.)
2007-12-03 08:08:36 · 1 answers · asked by Anna H 2 in Science & Mathematics ➔ Engineering
The speed of sound in dry air [m/s] is approximately 331.4 + (0.6 * temperature in degreesC). It is slightly higher for air with water vapor as is the case of the throat of the whooping crane, but not much higher.
A pipe with a closed end and an open end will resonate at wavelength 4 times the length of the pipe.
5.3 feet * 4 = 21.1 feet = 6.43 meters
speed of sound in air at 35C = 331.4 + (0.6 * 35) = 352.4 m/s
352.4 m/s divided by 6.43 m = 54.8 Hz
(Hertz is the same unit as "per second")
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2007-12-03 09:43:00 · answer #1 · answered by tlbs101 7 · 1⤊ 0⤋