Will the current in a light bulb connected to a 220-V source be greater or less than the current in the same bulb when it is connected to a 110-V source?
2007-12-03 07:52:17 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
V = I*R
Your R is constant (assuming the same light bulb is used). So you can just make up a value if all you are looking at is relationship... well use 1 for simplicity.
So solve for:
220 = I * 1
110 = I * 1
In which case is I greater and in which case is it less?
2007-12-03 07:56:12 · answer #1 · answered by Anonymous · 1⤊ 1⤋
ohm's law tells us that V = IR. Since it is the same light bulb, that means the resistance is constant. from 220 to 110, V decreases. From the equation, for constant R, I (current) is directly proportional to V (voltage). Since the voltage is decreased, so does the current. Therefore, current in the 220 V source is greater than the current in the 110 V source.
2016-05-28 00:44:30 · answer #2 · answered by ? 3 · 0⤊ 0⤋
It may be possible with certain bulbs to be the same but most likely the current will be lower at 110v. The resistance increases as the bulb heats up. The bulb will heat more with 220v connected so its resistance will be higher.
2007-12-03 08:57:59 · answer #3 · answered by Poor one 6 · 0⤊ 1⤋
The current will be greater as the resistance of the filament is the same regardless of the voltage. If the bulb is not rated for the higher voltage it will burn out, if not immediately, then very soon.
Joe4D is incorrect: voltage and current are directly proportional not inversely.
2007-12-03 07:59:10 · answer #4 · answered by Milldonkey 2 · 0⤊ 1⤋
constant R = V ^ 2 / W
light bulb designed rated at 110v used in 220v will have twice the current and four times the wattage and will burnt out in split of a second
2007-12-03 08:18:46 · answer #5 · answered by Anonymous · 1⤊ 1⤋
Assuming the light bulb was for use in a 110 volt circuit it might never survive an applied 220 volts. If it did survive it might briefly draw ½ or less current than the 110 volt circuit.
2007-12-03 08:05:03 · answer #6 · answered by peterngoodwin 6 · 0⤊ 4⤋
tricky
I think it could well be more
as the resistance (of tungsten) changes by 12 to 16 times from cold to incandescent and it's non-linear with voltage
far quicker to measure it
all those that used Ohms law (I=V/R) are hopelessly WRONG
and for the question to be valid we must assume it is rated for 220 volts (else it would pass no current if it burnt out)
Nil points to all of those answers too
2007-12-03 08:32:47 · answer #7 · answered by Anonymous · 0⤊ 1⤋
Current usually means amps so the amps would be less. As volts and amps are inversely proportional. But it really isnt a proper term as current sometimes is used to describe wattage or even the presence of electricity.
2007-12-03 07:57:31 · answer #8 · answered by sfcjoe4d 3 · 0⤊ 3⤋
Tricky... hahahah
V= I x R or I = V/R, R not changed, voltage doubled.......
2007-12-03 08:46:35 · answer #9 · answered by 1000 Man Embassy 5 · 0⤊ 1⤋