who should I contact to have it checked?
I havnt taken any yet.
2007-12-02 20:50:18 · 6 answers · asked by Anonymous in Health ➔ Other - Health
Im on propranolol, and they told me my new kind is from a different company called "Actavis"
So I looked it up on google, and I can see they have been in alot of trouble with the FDA for bad drugs
2007-12-02 21:08:31 · update #1
Atari, I asked a serious question, I want a serious answer, no jokes please
2007-12-02 21:16:08 · update #2
A generic cannot be sold if it is not equivalent to the brand. Propranolol is off patient. The medication is fine.
2007-12-03 01:15:24 · answer #1 · answered by Lea 7 · 1⤊ 0⤋
hmm this is interesting,
i highly doubt they would do this,
maybe they could of switched the wrong medicine's by accident,but even that is rare/almost impossible.
if you're acually worried,bring it to a different pharmacist,or the same one while different people are working,or you can even bring it to your doctor.
ask them to check it,say you think you've got the wrong pills or medicine/or you think there's something wrong with it(dont say bottle of poison lol )
then they'll check it out or w.e and call you,
dont take it til you get it done,
unless you feel you were misjudged the first time
Good luck
2007-12-03 05:03:30 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Why would you think that? If you are really concerned then take it to your doctor that prescribed it to you and have them check it out. To be honest they may prescribe you something else. OR you could take it to another pharmacy and have them inspect it.
2007-12-03 04:59:53 · answer #3 · answered by SassyLeo 3 · 1⤊ 0⤋
George Baily didn't do his job...
2007-12-03 04:53:31 · answer #4 · answered by Anonymous · 0⤊ 1⤋
You have to wonder why you think that, are they for paranoia.
2007-12-03 05:04:45 · answer #5 · answered by Dr. Atari 5 · 0⤊ 1⤋
that wasnt nice of them send it back with a note saying thanks but no thanks. seriously though just dont take it.
2007-12-03 04:59:14 · answer #6 · answered by justacontrygurl 2 · 1⤊ 0⤋