Two 1 1/2 V batteries are connected in series to a 3 ohm resistor. How much current flows through each battery

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Two 1 1/2 V batteries are connected in series to a 3 ohm resistor. How much current flows through each battery

2007-12-02 05:12:29 · 3 answers · asked by lp 1 in Science & Mathematics ➔ Engineering

3 answers

Ohm's Law: E = I x R

E = Voltage (volts)
I = Current (amps)
R = Resistance (ohms)

E = 1.5 V + 1.5 V = 3.0 V
R = 3 Ω

Solve the Ohm's Law equation for I

I = E ÷ R
I = 3.0 V ÷ 3 Ω = 1 amp

2007-12-02 09:45:29 · answer #1 · answered by Thomas C 6 · 0⤊ 0⤋

In a series circuit current is the same throughout the circuit.
Total voltage / total resistance = total current
3v/3ohms = 1 amp
1 amp flows through each battery.

2007-12-02 05:21:28 · answer #2 · answered by ? 3 · 0⤊ 0⤋

2amps should flow , Individually - I feel .

2007-12-10 01:41:36 · answer #3 · answered by Naaraayanan 3 · 0⤊ 0⤋