AC theory HELP!?

Question

Puhleese help me on this one, electronic engineers out there!

Vpk=1V, Vrms = √2 V, Rsourcevoltage = 50Ω (bummer#1) L=56mH, Rinductor = 56Ω(bummer#2), C=100nF, Rload=120Ω

Find: impedance, circulating current (thats Ipk or Irms??? :-S), and VOLTAGES across EACH COMPONENT (megabummer) using theoretical as well as complex analysis.

I know internal resistances can be summed with load as series resistance, but what about the Icirculating (pk or rms???), and VOLTAGE? Do i find voltage across(L+Rinductor) or what?

{lease solve the entire question with steps, if that's not too much to ask. I'm sure there are people who love such questions and are raring to go.

Well? Help!

Quite seriously im taking this que to heart as its a major percent of my finals, the nose bleeds are not stopping. Really.

oopsie my bad keep helping!

frequency is 1KHz

it is a series LCR

Vpk =1V 0Deg

Answer 1

Your question isn't clear. Are all the components in series? Vrms = V/√2 if V is 0-to-peak. What is the frequency of the source?

Assume you have the inductor and capacitor in series; then the load is also in series and you have a single loop circuit.

The impedance of the loop is Zloop = Rsource + Rinductor + Rload + j2πfL + 1/(j2πfC)

The rms current in the loop is Iloop = Vrms/Zloop

Then the voltage across each component is

Vcomp = Iloop*Zcomp

Zinductor = j2πfL (EDIT: if Rinductor is the inductor internal resistance then Zinductor = Rinductor + j2πfL)

Zcapacitor = 1/(j2πfC)

Zresistor = R

j = √-1

If the voltage source is sinusoidal, you can use either Vpeak or Vrms as long as you are consistent throughout.

I don't know what you mean by "theoretical' as opposed to complex analysis. Perhaps you mean using differential equations defining the current/voltage relations of the components:

Vinductor = L*di/dt Vcapacitor = (1/C)*∫idt

Write the sum of all voltages in the loop and equate to source voltage

∑Ri + L*di/dt + (1/C)*∫idt = V

Differentiate through

∑Rdi/dt + Ld^2i/dt^2 + (1/C)i = dV/dt

If V(t) = V*sin2πft, then dV/Dt = 2πfVcos2πft

Now you have to find the steady-state solution to this. The complex variable method is much easier.

Answer 2

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Answer 3

why don't you just leave school.. school is for fools .. who needs school any way,, even if you get your degree, you won't get a job,, so go get money,, and don't waste more years of your life for nothing,, many of the most richest people in the world don't have a degree..
be cool, and stop asking silly questions about things you know that it is not your field of interest,, even if you got it right this once ,, you will not remember this within next week,, it is something you hate,, go find a talent and be good at,, and don't listen to your mum, you are not a child anymore. you can pee alone ,, right ?

Answer 4

You have not atated the supply frequency in radians/se. If w is the frequency then impedance of inductor is jwL and that of capacitor is 1/jwC where j=sqrt(-1). Then you can apply ohms law with complex numbers.