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For all you Power Engineers and Thermodynamicists out there. We have 90mL of water sitting at the end of a non-insulated pipe. The water drained out from a steam trap valve located at the outlet. We know the temperature of the inlet steam but not the condensed water (has not been sitting long enough to be room temp.) How do we convert this volume to a mass?

2007-11-30 06:12:46 · 3 answers · asked by Chubbs20 2 in Science & Mathematics Engineering

3 answers

Volume divided by specific volume equals mass.

2007-11-30 16:14:35 · answer #1 · answered by Tim C 7 · 0 0

Specific Volume Conversion

2016-11-07 09:25:43 · answer #2 · answered by ? 4 · 0 0

The enthalpy of the water in the pipe will be that of saturated liquid at the pressure in the pipe.

After it passes through the steam trap, it will turn into vapor and liquid at atmospheric pressure.

So if x is the fraction of water, (1-x) will be the fraction of vapor.

x * (enthalpy of water at atmospheric) + (1-x)*(enthalpy of vapor at atmopheric pressure) = enthalpy of the original water in the pipe at pressure.

Then multiply times the 90 g of water you started with (actually 90 ml * specific volume of water at the upstream pressure), to get the mass of gas & liquid.

2007-11-30 13:08:00 · answer #3 · answered by Doug B 3 · 0 0

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