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r= 4sin x

r^2= cos x

2007-11-29 17:56:19 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

I assume you mean:

r = 4sinθ
and
r² = cosθ
_________

Remember the identities.

x = rcosθ
y = rsinθ
x² + y² = r²
_________

r = 4sinθ
r² = 4rsinθ
x² + y² = 4y
x² + y² - 4y = 0
x² + (y² - 4y + 4) = 4
x² + (y - 2)² = 4

This is a circle with center (0,2) and radius 2.
___________

r² = cosθ
r³ = rcosθ
(x² + y²)^(3/2) = x
____________

2007-11-30 16:00:14 · answer #1 · answered by Northstar 7 · 0 0

r^2 = 4rsin(theta)
y = rsin(theta)
r^2 = x^2 + y^2

x^2 + y^2 = 4y

2007-11-29 18:22:31 · answer #2 · answered by Axis Flip 3 · 0 0

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