Original Question:
Two sides of a particular isosceles triangle are 6 and 13 unites. What is the area of this triangle? Express your answer in simplest radical form.
2007-11-29 16:40:26 · 3 answers · asked by Bobby S 3 in Science & Mathematics ➔ Mathematics
6 is base of isosceles triangle.
h is height
13² = h² + 3²
h² = 13² - 3²
h² = (13 - 3)(13 + 3)
h² = 160
h = 4√10
Area = (1/2) (6) (4) √10 units²
Area = 12√10 units²
2007-11-30 02:56:49 · answer #1 · answered by Como 7 · 3⤊ 1⤋
let the 6 unit side be the base of the triangle.
Using Pythagarus's theorem,
the height of the triangle = sqrt(13^2 - 3^2)
= sqrt 160
= 4 sqrt10
Area = 1/2 (6) (4 sqrt10)
=12 sqrt 10
2007-11-30 00:51:15 · answer #2 · answered by jervois.east 2 · 2⤊ 1⤋
The area of a triangle is 'base' times 'height' divided by 2. So I think the answer's 6 times height / 2.
2007-11-30 00:50:15 · answer #3 · answered by gabe 3 · 1⤊ 1⤋