2007-11-29 15:51:31 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
10 and 12
10x12=120
2007-11-29 15:54:28 · answer #1 · answered by John 4 · 1⤊ 0⤋
Let x be an integer.even integer means it must be divisible by 2.
Let 2x and 2x+2 be two cosecutive even +ve integhers,.
2x(2x+2)=120
4x^2+4x=120
or
4x^2+4x-120=0
the multiples of 4 and 120
4x120=30x16
=5x2x4x4x3
4x^2+24x-20x+120=0
4x(x+6)-20(x+6)=0
so x=5 or-6
so the consecutive integers r 10 and 12.
2007-11-29 16:05:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋
n (n+2)=120
n*n + 2n - 120 = 0
(n+ 12 ) (n- 10 ) =0
10, 12
2007-11-29 15:56:28 · answer #3 · answered by Lady Lefty 3 · 0⤊ 0⤋
10(12)?
2007-11-29 16:14:50 · answer #4 · answered by Lightbringer 6 · 0⤊ 0⤋
x(x+2)=120
(x^2) + 2x - 120 = 0
solve it to get one answer
and add two to get the other
2007-11-29 15:55:53 · answer #5 · answered by hameerabbasi 3 · 1⤊ 0⤋