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please solve these single replacement reactions! PLZ TRY INCLUDING STEPS

1. zinc metal is placed in a solution of copper (II) sulfate
2. a small piece of sodium metal is added to distilled water
3. Chlorine gas is bubbled into a solution of sodium iodide

FIRST ONE TO ANSWER N SHOW STEPS CORRECTLY GETS 10 PTS!

2007-11-29 14:49:31 · 4 answers · asked by !!!!!! 3 in Science & Mathematics Chemistry

4 answers

1. Zn + CuSO4 ===> ZnSO4 + Cu

2. 2Na + 2H2O ===> 2NaOH + H2

3. Cl2 + 2NaI ===> 2NaCl + I2

2007-11-29 14:55:18 · answer #1 · answered by steve_geo1 7 · 0 0

Zinc Copper Ii Sulfate

2016-11-09 12:04:12 · answer #2 · answered by joerling 4 · 0 0

1) Zn + CuSO4 > Cu + ZnSO4
Cu prefers to be an atom rather than an ion when compared to Zn and will be replaced by Zn

2) 2Na + 2H2O > 2NaOH + H2
If you look at H20 as H+ and OH-, then Na will want to be an ion more than H does, and will replace H

3) Cl2 + 2NaI > 2NaCl + I2
Cl prefers to be an ion more than I does and will thus replace I

2007-11-29 15:45:42 · answer #3 · answered by Raggle Fraggler 2 · 1 1

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the copper precipitates out of the solution and zinc sulfate forms... its a pretty simple single displacement reaction.

2016-04-06 00:55:13 · answer #4 · answered by Anonymous · 0 0

1. Zn + CuSO4 -> ZnSO4 + Cu
2. Na + H20 -> NaO + H2
3. Cl2 + 2NaI -> 2NaCl + I2

2007-11-29 14:55:01 · answer #5 · answered by Dani 4 · 2 3

1. Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s)

No steps to show.

2. 2Na(s) + 2H2O(l) --> 2NaOH(aq) + H2(g)

3. Cl2(g) + 2NaI(aq) --> 2NaCl(aq) + I2(s)

2007-11-29 14:58:42 · answer #6 · answered by papastolte 6 · 0 1

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