2007-11-29 13:35:44 · 4 answers · asked by derrim2000 1 in Science & Mathematics ➔ Mathematics
solve for x?
It's approx. -2, -3, and -0.5
If you want to factorize it, it is : (x+2)(x+3)(x+0.5)
2007-11-29 13:43:05 · answer #1 · answered by wangsacl 4 · 0⤊ 0⤋
Write 2x^3 + 11x^2 + 17x + 6 as (x + a)(2x^2 + bx + c) as a starting point to factor the equation, you might also try
(2x + a)(x^2 + bx + c) is this doesn't work.
Since the constant is 6, then a x c = 6, so try factors of 6 for a and c, then try various values for b that will get 11x^2 and 17x.
2x^3 + 11x^2 + 17x + 6 = (x+3)(2x^2+ 5x + 2)
Further factor (2x^2+ 5x + 2)=(2x+1)(x+2).
Complete factorization is (x+3)(2x+1)(x+2)=0, so that
x=-3, x=-1/2, x=-2
2007-11-29 21:55:19 · answer #2 · answered by LDJ 3 · 0⤊ 0⤋
-1/2, -2, -3
2007-11-29 21:44:30 · answer #3 · answered by catsfanj 3 · 0⤊ 0⤋
x=-1/2
x=-2 and x=-3
2007-11-29 21:41:16 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋