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im really confused on how to do this problem. its says- there are four consecutive odd integers. the sum of the first and the second numbers is 96. what are the integers?

im pretty sure you have to do let statements. so i made four.
let x+2=1st number
let x+4=2nd number
let x+6=3rd number
let x+8= 4th number

it says odd integers, and im pretty sure i remember learning that odd integers were the same as even integers. correct me if im wrong.

but then it says the sum of the first and second. which i can do

x+2+x+4=26

but i dont understand how doing that problem can help you figure out all four of the integers. does anyone know?

2007-11-29 13:35:32 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

i dont get it, HOW did you get those answers?

2007-11-29 14:00:53 · update #1

3 answers

The first and the second integers add to 96. Now the first and the second integers differ by two since they are consecutive. That means that if you subtract two, then the first integer doubled is 94, and therefore the first integer is 47. The integers are therefore 47,48,49,50.

EDIT: My bad - I misread the question. Consecutive ODD integers. They are 47,49,51,53

2007-11-29 13:43:52 · answer #1 · answered by KeplJoey 7 · 0 0

let the four consecutive integers be x,x+2,x+4 and x+6. The sum of the first two are x+(x+2)=96 => x=47
the others are
x+2=49
x+4=51
x+6=53

2007-11-29 21:46:16 · answer #2 · answered by mwanahamisi 3 · 0 0

2n-1+2n+1=96 so 4n = 96 and n=24
The integers are
47,49,51,53

2007-11-29 21:44:22 · answer #3 · answered by santmann2002 7 · 0 0

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