Algebra question; solve this equation 2x squared -x=3. Factor this problem. Can anyone help me?

Answer 1

2x^2-x=3
subtract 3
2x^2-x-3 = 0
factor
(2x-3)(x+1)=0
that means either 2x-3 = 0 or x+1=0
so x =3/2 or x = -1

Answer 2

(x+1)(2x-3)

don't ask me how i got it, it's right.

okay, fine, here's the work:
subtract three to the other side so that you have all the numbers on the left side equaling zero. next you use this method where you multiply 2x squared by 3 (the first and last times each other) you get -6. then you figure out what multiplies to negative six and adds to -1 (because the middle term is -x which is also known as -1x). the answer for that is -3 and 2. next you factor it out. you end up with
x(2x-3) + 1(2x-3). you factor a little more and end up with (x+1)(2x-3)

Here are the steps with the math and the numbers:
2x^2 - x = 3
2x^2 - x - 3 = 0
2x^2 - 3x + 2x - 3 = 0
x(2x-3) + 1 (2x-3)
(x+1)(2x-3)

hope that helps and made a little bit of sense. if it didn't, well, i can assure you that that answer is right. you can trust me.

Answer 3

2x^2-x = 3
Moving all of the terms to one side, we get: 2x^2-x-3=0

From there, we can factor to solve for x: (2x-3)(x+1)=0

Any number multiplied by 0 equals 0, so:
2x-3=0 or x+1=0

Isolating x to get our final answer, we get:
x=3/2 or x=-1

Answer 4

2xsquared -x =3
2x squared -x -3 =0
(2x -3)(x +1) = 0

Answer 5

first - let's get everybody on the same side = 0
so - subtract 3 from both sides....yields
2x^2 - x -3 = 0
2 factors (1,2) and 3 factors (1,3)
NOW - since BOTH are minuses - one will be positive and the LARGER will be the minus
(2x-3)(x+1) = 0

all the best !

Answer 6

2x^2 - x - 3 = 0
(2x -3) (x+1) = 0