projectile motion?

Question

An astronaut is golfing on the moon, which has gravity of 1.63m/s^2 down. If he hit the ball and it left the tee with an initial velocity of 15m/s at an angle of 26 degrees, how much time does the ball spend in the air? How far does the ball travel from the tee?

Answer 1

The time to apogee is 1/2 the total flight time
vy(t)=15*sin(26)-1.63*t
when vy(t)=0 we have apogee
time to apogee is 4.034 sec
total flight time is
8.068

the range is
x(t)=15*cos(26)*t
109 m

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