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The graph of the function touches or corsses the x-axis wherever the value of the function is zero. So we must solve 3x^2 + 8x + 5 = 0. We can factor this into (3x + 5)(x + 1) = 0 So the function has a value of zero when 3x + 5 = 0 ==> x = -5/3 or x + 1 = 0 ==> x = -1. So there are two values of x where the function touches or crosses the x-axis.

2007-12-02 07:04:11 · answer #1 · answered by DavidK93 7 · 0 0

twice

2007-11-29 21:17:23 · answer #2 · answered by andrew 2 · 0 0

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