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1) -3,2
2) -1,4
3) -6,3
4) 2,5
5) -6,1
6) -10,2
7) 2,3
8) -5,-2
9) -3,5
10) 12,1
11) -8,2
12) -5,10
13) -7,5
14) -5,6
15) -8,4

2007-11-29 12:33:37 · 2 answers · asked by erikjjjacob 1 in Science & Mathematics Mathematics

2 answers

I won't do fifteen of these, but the method is simple enough:

If x = -3 and x = 2 are roots, then

[x - (-3)] (x - 2) = 0, or
(x + 3)(x - 2) = 0, or
x² +3x - 2x - 6 = 0, or
x² + x - 6 = 0

2007-11-29 12:41:25 · answer #1 · answered by anobium625 6 · 1 0

Ijust do the first one for you
[x-(-3)][x-2]=x^2+x-6

The rest are yours.

2007-11-29 20:43:43 · answer #2 · answered by mwanahamisi 3 · 0 0

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