Simplify: 3 - i /2 + i. (i meaning imaginary number)?

Answer 1

Assume that there ought to be brackets:-
(3 - i) / (2 + i)
= (3 - i) (2 - i) / (2 + i)(2 - i)
= ( 6 - 5 i + i ²) / (4 + 1)
= ( 5 - 5 i ) / 5
= 1 - i

Answer 2

i - i/2 = i/2
Think it out yourself now.
-----
EDIT: I'm guessing you're talking to me -.-
3 - i/2 + i at what it looks like NOW is 3 + i/2.
Judging from your answer you have misread it.
3 - (3i/2) = 3 - i/2 - i
Now let's suppose the question is actually:
(3-i) / (2+i)
We can multiply by its conjugate and get:
[(3-i)(2-i)]/(4+1) = (6 - 3i - 2i - 1) / 5 = (5 - 5i) / 5 = 1 - i

And i has a definite value. It is even more wrong to say that since there is no assigned vlaue that my equation is wrong. My equation is absolutely 100% correct backed up by a military of rules. It's basic algebra. And yea, a - a/2 = a/2. b - b/2 = b/2. c - c/2 = c/2. Basic algebra I tell you.

i = sqrt -1

Answer 3

3-[(3i)/2]
the other one cannot be right because you don't know what its equal to
and that one he is assigning i a number

(6-3i)/2