Write an equation for a line with slope 2/3 that passes through the point (3,6).?

Answer 1

Start with the point-slope form of a line:

y - y1 = m(x - x1)

Here m is the slope = 2/3
(x1, y1) is the point (3, 6)

So the equation is:
y - 6 = (2/3)(x - 3)

If you need it in slope-intercept form, distribute the 2/3 through:
y - 6 = (2/3)x - (2/3)3
y - 6 = (2/3)x - 2

Now add 6 to both sides:
y = (2/3)x + 4

Answer 2

general equation is:
y = ax + b

a is a slope, therefore your a is 2/3
y =2/3x + b
No substitute the coordinates of (3,6) to the equation(x = 3, y = 6)
6 = 2/3 * 3 + b
6 = 2 + b
b = 4

your equation is:
y = 2/3x + 4

Answer 3

Point slope (general equation for a point and a slope):

y-(yvalue)=slope*(x-xvalue)
(xValue,yValue)=(3,6)::Slope=2/3
y-6=(2/3)(x-3)
Now multiply out:
y-6=(2/3)-2
y=(2/3)x+4

Answer 4

y=mx+b
6=2/3(3)+b
b=4

equation is: y=2/3x+4