Math help please!?

Question

Here's the question:

"Given a well shuffled standard 52 card deck of playing cards(which contains 13 cards in a four suits and 3 face cards in each suit) what is the probability that you draw a red card or a face card on the first draw?"

they gave me a hint too: "it could be both."

Answer 1

There are 26 red cards. And there are 12 face cards (3 x 4 suits). But this double counts the red face cards. So you want to subtract 6.

26 + 12 - 6 = 32 "good" cards / 52 possible cards

= 32/52
= 8/13
≈ 61.5%

Answer 2

it is 26 out of 52 that it is red: because there are 26 red cards in the deck of 52 that you could get.
it is 12 out of 52 that it is a face because there are 3 face cards per suit and 3 suits so you multiply 3(faces) by 4(suits) and get 12
it is 6 out of 52 that you could get a red face value card because there are 2 red suits and 3 faces per suit so you multiply 2(red suits) by 3(faces) and get 6

the clue is either for the red faced card or that you can use both the face & color in the problem.......does that help?