2007-11-29 10:42:24 · 8 answers · asked by Chuck B 2 in Science & Mathematics ➔ Mathematics
(3x - 1)(3x + 1)
Check
9x² + 3x - 3x - 1
9x² - 1 (as required)
2007-12-03 09:32:51 · answer #1 · answered by Como 7 · 0⤊ 0⤋
ok, first of all ill go thorugh the steps of factoring.
9X^2+ 0X -1
first thing, you want to find 2 factors, which their product is
-9X2 and the sum is 0. After some work you will find out ther factors are 3x and -3x.
So sub that into the equation.
(9X^2+3x)-(3x+1)
then factor the first 2 terms in the expression
3X(3X+1) -1(3X-1)
Therefore, conect the outside term into 1 factor, and the common into another
like:
(3X-1)(3X-1)= (3X-1)^2
2007-11-29 18:54:55 · answer #2 · answered by Plain Silly 4 · 0⤊ 0⤋
You look at the two parts and see if they have square roots-
Root of 9x^2 is 3x.
When you look at -1, you know that it's the product of 1 & -1.
So,
(3x - 1) (3x + 1)
2007-11-29 18:50:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Whenever theres a (-1) in a problem like this, just remember SPAM. Square root of the first number (The "3x"s) PLUS one And Minus one. (3x+1)(3x-1)
2007-11-29 18:51:42 · answer #4 · answered by Cameron 2 · 0⤊ 0⤋
Just a simple difference of squares:
(3x+1)(3x-1)
2007-11-29 18:49:46 · answer #5 · answered by Rance D 5 · 0⤊ 1⤋
9x² - 1
. . = ( 3x )² - ( 1 )²
. . = ( 3x + 1 ) ( 3x - 1 )
2007-11-29 18:46:28 · answer #6 · answered by Ben 3 · 0⤊ 1⤋
(3x+1)(3x-1)
2007-11-29 18:45:05 · answer #7 · answered by Anonymous · 0⤊ 1⤋
(3x-1)(3x+1)
2007-11-29 18:44:59 · answer #8 · answered by HcAeLxXaM 3 · 0⤊ 1⤋