a. 13.5
b. 13
c. 12.943
2007-11-29 10:14:45 · 11 answers · asked by ♥ ღAngelicaღ♥ 2 in Science & Mathematics ➔ Mathematics
x² = 5² + 12²
x² = 25 + 144
x² = 169
x = 13
OPTION b
2007-12-03 04:01:36 · answer #1 · answered by Como 7 · 1⤊ 0⤋
13
2007-11-29 18:19:20 · answer #2 · answered by Anonymous · 1⤊ 0⤋
13
x^2 = y^2 + z^2
x^2 = 5^2 + 12^2
x^2 = 25 + 144
x^2 = 169
x = 13
You should learn off by heart:
3:4:5
5:12:13
6:8 : 10
7:24:25
8: 15: 17
at the least
(One piece of useless knowledge)
Every integer higher than 2 can be used in a right angle triangle such that the other two sides are integers.
There are no integer solutions of x^n + y^n = z^n where n>2 (except trivial ones i.e.x | y | z = 0
2007-11-29 18:19:24 · answer #3 · answered by welcome news 6 · 0⤊ 0⤋
a^2+b^2= c^2
12^2+5^2=
144+25= 169
square root of 169= B. 13
2007-11-29 18:23:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
pythagorium therom
a^2 +b^2= c^2
12^2+5^2=c^2
c= 13 ft the hypotenuse
2007-11-29 18:21:57 · answer #5 · answered by Norgbirdie 2 · 0⤊ 0⤋
a^2 + b^2 = c^2
12^2 + 5^2 = c^2
144 + 25 = c^2
c = sqrt(144 + 25)
c = sqrt(169)
c = 13
2007-11-29 18:19:28 · answer #6 · answered by Anonymous · 0⤊ 0⤋
ok its going to be
a^2 + b^2 = c^2
a and b are legs, and c is the hypotenuse
12^2 + 5 ^ 2 = c^2
144 + 25 = c^2
169 = c^2
+/- 13 = c
2007-11-29 18:18:56 · answer #7 · answered by Bollywood Masti 4 · 1⤊ 0⤋
b 13 use pythagorean theorem a^2 + b^2 = c^2
2007-11-29 18:19:41 · answer #8 · answered by arthur 1 · 1⤊ 0⤋
c^2=a^2+b^2
c is the hypoteneuse, so
c^2=(12)^2+(5)^2
c^2=169
c= 13
2007-11-29 18:24:20 · answer #9 · answered by Kelly 3 · 0⤊ 0⤋
12^2+5^2=hyp^2
144+25=c^2
169=c^2
c=13
answer b
2007-11-29 18:18:02 · answer #10 · answered by RickSus R 5 · 1⤊ 1⤋