Simplify this someone, please..(2+i)-(4-2i)?

Question

(3-i)(3+i)

(-6i)(4i)

I know it seems grade school but I really need help doing this!

Answer 1

(3 - i)(3 + i)

Use the FOIL method:

First:
3 x 3 = 3² = 9

Outer:
3 x i = 3i

Inner:
-i x 3 = -3i

Last:
-i x i = -i² = -(-1) = 1

Now just add them all up:

9 + 3i - 3i + 1

A couple terms (+3i and -3i) cancel out:

Answer = 10

PROBLEM 2:

Multiply the numbers and then the i terms:

(-6i)(4i)
= -6 x -4 x i²
= -24 x -1
= 24

Answer 2

(2+i) - (4-2i) (by the way i stands for the square root of -1)
2 + i - 4 + 2i
-2 + 3i or 3i -2

(3-i)(3+1) (this is your basic binomial square)
9 +3i -3i -i^2 (Using FOIL)
9 + i^2 (simplifying, +3i -3i = 0)

(-6i)(4i) = -24i^2 (too easy for explanation)

Answer 3

1. Add the real and imaginary parts separately to get
-2 + 3i.
2. Use your FOIL rule to get 9 + 1 = 10.
3. Since i² = -1 the answer is 24.

Answer 4

8-2i^2

9+i^2

-24i^2

Answer 5

This is all you need to know to solve them for yourself:
(x+a)(x-a) = x² -a²
i² = -1

Answer 6

top= 9-isquared

bottom= -24i