an ape is capable of jumping to a height of 15.0m. Determine the takeoff speed of the ape.?

Question

HELP!

Answer 1

Use conservation of energy:

Kinetic energy - potential energy = constant = 0 when all potential is converted to kinetic and vice versa.

So that means KE = PE or

1/2mv^2 = mgh where g = acceleration of gravity, h = height at top of jump, m = mass of ape, and v = speed at take-off

Then

v^2 = 2gh ---> v =sqrt(2*g*h) = sqrt(2*9.8*15) = 17.14 m/s

Answer 2

Change this to a downward acceleration problem and it is easier to solve.

At the peak of his jump, the ape's vertical velocity is zero. He then falls in an exact inverse of the speed when he rose, meaning that he hits the ground at his takeoff velocity.

You can do the calculations for him falling from 15.0m, right? So, if an ape falls from 15.0m, at what velocity will he hit the ground?

Answer 3

Let the initial vel. be 'u'
Final velocity = 0 m/s
Acceleration due to gravity = 9.8 m/s²
v² - u² = 2 g h
15 = (v² - u²) / 2 g = 0² - u² / 2 x - 9.8 = u² / 19.6
u² = 15 x 19.6 = 294 m/s
Hence, take off speed = √294 = 17.15 m/s
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Answer 4

Wouldn't the initial take off speed just be 0? If the ape's on the ground, and not doing anything prior to the jump, the initial speed would be zero.

Answer 5

No ape can jump up 15 meters, except for the ones in the Apelympics.

Answer 6

That all depends of the air's consistency, the strength of wind, the type of ape, the apes weight, etc.

Answer 7

What is this, a good day for everyone to do someone else's homework?

I don't give a blank about the points, but I'll tell 'ya, when did Yahoo! Answers turn into
"Do - My - Homework - For - Me - For - 10 - Points!"???

Answer 8

king Kong

Answer 9

23.

Answer 10

Twice that of his landing speed.