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12k(1/4k^2-2/3)(k^2+1) How would I solve this using the foil method with fractions?

2007-11-29 09:01:25 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Just like one without fractions:

12k[(1/4)k^3+(1/4)k^2-(2/3)k^2-2/3]
3k^3+3k^2-8k^2-8
3k^3-5k^2-8

2007-11-29 09:05:53 · answer #1 · answered by someone2841 3 · 0 0

okay first you have to distribute the 12k inside the first set of parentheses. you get

(3k^3 - 8k) (k^2 +1)

now just use the foil method

you get

3k^5 + 3k^3 - 8k^3 - 8k

the answer when you combine like terms is:

3k^5 - 5k^3 - 8k

2007-11-29 17:07:18 · answer #2 · answered by Anonymous · 0 0

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