factor completely. 5x^2+xy+5x+y?

Question

I am not sure how to do this. If you could please just explain the steps, I am sure I can figure it out. Thank you in advance for your help.

Answer 1

(x) (5x + y) + (5x + y)
(5x + y) (x + 1)

Answer 2

5x^2 + xy + 5x + y

Grouping - factor an x from the first two terms and a 1 from the second two

x(5x + y) + 1(5x + y)

This has the form of the right side of

a(b + c) = ab + ac

where (5x + y) is equivalent to the a

(5x + y)(x + 1)

Answer 3

Look at the 1st and 3rd terms:

Here you can factor out a common 5x:

5x(x + 1) + xy + y

Now look at the other terms. Here you can factor out a common y:
5x(x + 1) + y(x + 1)

Cool! Now we can factor out a common (x + 1)
(5x + y)(x + 1)

P.S. It also works if you factor out an x from terms 1 and 2... take it from there to get the same answer.

Answer 4

Rearrange it :5x^2+5x+xy+y
=5x(x+1)+y(x+1)
=(x+1)(5x+y)
GOOD LUCK

Answer 5

Hey there!

Here's the answer.

5x^2+xy+5x+y --> Write the problem.
(5x^2+xy)+(5x+y) --> Place the parentheses arund 5x^2+xy and 5x+y).
x(5x+y)+1(5x+y) --> Factor out the x in 5x^2+xy and 1 out of 5x+y.
(x+1)(5x+y) Factor out x+1.

So the answer is (x+1)(5x+y).

Hope it helps!

Answer 6

OK

5x^2 +xy +5x +y =

5x^2 + 5x + xy + y =

5x(x+1) +y(x+1)

(5x+y)(x+1)

Hope that helps.

Answer 7

(5x+y)(x+1)

simply, what numbers add to get b (in ax + bx+c, i just coponverted it to fit this) and what times to get c. i used almost trial and area, first i tried 5x and x to get 5x^2 so far:

(5x+)(x+)

now, you only have y so that is 1, so it means it must not go in the bracket containing x so they can multiiply to get xy.

(5x+y)(x+1)

if it was (5x+1)(x+y) it would be solved as 5x^2 + 5xy + x + y

good luck. :)

Answer 8

x ( 5x + y ) + 5 x + y = ( 5 x + y ) ( x + 1 )