chemistry help!? (moles)?

Question

Identify the limiting reactant when 7.81g HCl reacts with 5.24g of NaOH to produce NaCl and H2O.

please go through all of the steps

Answer 1

HCl + NaOH ===> NaCl + H2O

Atomic weights: H=1 Cl=35.5 HCl=36.5 Na=23 O=16 NaOH=40

7.81gHCl x 1molHCl/36.5gHCl = 0.214 mole HCl

5.24gNaOH x 1molNaOH/40gNaOH = 0.131 mole NaOH

Because there are fewer moles NaOH, it will run out first; it is the limiting reagent.

Answer 2

HCl MW = 36.46 g/mole
NaOH = 39.9971 g/mole

7.81 g HCl = 7.81g * mole/36.46g = 0.214 moles HCl

5.24 g NaOH = 5.24 g * mole/39.9971 g = 0.131 moles NaOH

reaction is

HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)

1 moles HCl reaction with 1 mole NaOH

you have 0.131 mole NaOH and 0.214 mole HCl

HCl is WAY in excess so NaOH is the limiting reagent